Thursday, June 1, 2017

How To Add Improper Fractions Khan Academy



we're asked to multiply 5/6times 2/3 and then simplify our answer. so let's just multiplythese two numbers. so we have 5/6 times 2/3. now when you're multiplyingfractions, it's actually a


How To Add Improper Fractions Khan Academy, pretty straightforwardprocess. the new numerator, or thenumerator of the product, is just the product of the twonumerators, or your new top number is a product of theother two top numbers.


so the numerator in our productis just 5 times 2. so it's equal to 5 times 2 over6 times 3, which is equal to-- 5 times 2 is 10 and6 times 3 is 18, so it's equal to 10/18. and you could view this aseither 2/3 of 5/6 or 5/6 of 2/3, depending on how youwant to think about it. and this is the right answer. it is 10/18, but when you lookat these two numbers, you immediately or you mightimmediately see that they


share some common factors. they're both divisible by 2,so if we want it in lowest terms, we want to dividethem both by 2. so divide 10 by 2, divide 18 by2, and you get 10 divided by 2 is 5, 18 dividedby 2 is 9. now, you could have essentiallydone this step earlier on. you could've done it actuallybefore we did the multiplication.


you could've doneit over here. you could've said, well, i havea 2 in the numerator and i have something divisible by 2into the denominator, so let me divide the numerator by2, and this becomes a 1. let me divide the denominatorby 2, and this becomes a 3. and then you have 5 times 1is 5, and 3 times 3 is 9. so it's really the same thingwe did right here. we just did it before weactually took the product. you could actuallydo it right here.


so if you did it right overhere, you'd say, well, look, 6 times 3 is eventually goingto be the denominator. 5 times 2 is eventually goingto be the numerator. so let's divide the numerator by2, so this will become a 1. let's divide the denominatorby 2. this is divisible by 2,so that'll become a 3. and it'll become 5 times 1is 5 and 3 times 3 is 9. so either way you doit, it'll work. if you do it this way, you getto see the things factored out


a little bit more, so it'susually easier to recognize what's divisible by what, or youcould do it at the end and put things in lowest terms.


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