How To Add Fractions In Matlab

in this simulation we are looking at chemicalequilibrium fro gas phase reaction, simple a goes, in this case, a goes in to 2 b wherewe can change the number 2 to 3/2, 1 or 1/2. and we have two options. so here, let's lookat a snapshot of what this looks like. we are showing the constant pressure option,so select the pressure with the pressure slider, and then what the simulation then calculates,is the number of moles at equilibrium, where

How To Add Fractions In Matlab, we start with 5 moles of a at 1.2 bar andthen we let it go to equilibrium. and because 2 moles of b form for every mole of a, thenumber of moles a+b of course is greater than 5. we also have the option of adding in insertsto see what effect that has on equilibrium. and the simulation calculates the final volumein this case. and the piston then moves up

or down as we change the starting pressureor add more inert to the system. and the idea here is, one, to observe the effect of addingan inert, and you should understand why that is going to affect the reaction and how it'sgoing to have a different effect if it is a goes to b or a goes to 1/2 b instead of2 b. and the other is to look at equilibrium in a constant volume situation. so again westart with 5 moles and we select the pressure to start with, but the pressure is going tochange as we go to equilibrium. and likewise we can add inert to that system. so the bargraph is the number of moles, of course this changes if we move the sliders. and so wewill look at the simulation to understand the behavior a little better. so here we arelooking at the simulation. we are looking

at the case where we have 1 mole of a reactingto form 2 moles of b. and this is the constant pressure, if i increase the pressure of coursevolume is less because we are fixing the number of moles of a initially. increasing the pressure,you notice, pushes the equilibrium more a and less b. if i instead addd an inert, iam pushing equilibrium now to make more b and less a because we are just lowering thepartial pressures. if i instead looked at one mole of a forms 1 mole of b and this isa gas phase reaction. then the inert doesn't make a difference because we don't have amole change so the difference doesn't affect the reaction. but look at the constant volumecase. now the initial pressure just determines what our initial volume is. and then thatinitial volume is fixed. so the initial pressure

a goes to b pressure doesn't change. if ilook at a goes to 2 b. notice now that the final pressure is 0.82 whereas initial pressurewas 0.6. the volume was fixed. if i increase the pressure initially that just decreasesthe initial volume, that initial volume, of course, is our fixed value. let's just backthat all up. if i add inert, notice nothing happens. any of these reactions. the inerthas no effect because we are assuming ideal gases, inert doesn't change the partial pressures,it doesn't change anything in the equilibrium expression. so looking at these two caseswe can see how equilibrium is affected by pressure, by the presence of inserts in twodifferent conditions, under constant pressure and constant volume.